SOLUTION: for the function y=x2-4x-5, perform the following tasks:
a) Put the function in the form y=a(x-h)2 +k ....the 2 after x is x squared, and the 2 after h is (x-h)squared
b)what is
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-> SOLUTION: for the function y=x2-4x-5, perform the following tasks:
a) Put the function in the form y=a(x-h)2 +k ....the 2 after x is x squared, and the 2 after h is (x-h)squared
b)what is
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Question 31878: for the function y=x2-4x-5, perform the following tasks:
a) Put the function in the form y=a(x-h)2 +k ....the 2 after x is x squared, and the 2 after h is (x-h)squared
b)what is the line of symmetry?
c) Graph the function using the equation in part a. Explain why it is not necessary to plot points to graph when using y=a(x-h)2 +k (the 2 after (x-h) is squared
d) how does this graph compare to the graph of y=x2(xsquared) Answer by longjonsilver(2297) (Show Source):
2a=-4
--> a = -2
and so --> the +4-4 is zero, so we haven't actually altered the equation.
which is now of the form required.
b. Line of symmetry is x=2
c. We know the apex of the curve...it is (2,-9) and the term is positive, meaning it is u-shaped rather than n-shaped. So we get . However, purely looking at the equation in this form does not "instantly" tell us the intercepts on the axes... some algebra, minimal yes, is still required.
d. moved by 2 units to the right gives and then this moved by 9 units down is given by
Here are all 3 stages: , and on the same scales, so you can see them:
