SOLUTION: Find three consecutive integers such that the square of the sum of the smaller two is 297 more than the square of the largest.

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Question 318736: Find three consecutive integers such that the square of the sum of the smaller two is 297 more than the square of the largest.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let the integers be x, x+1, x+2
..
(x+x+1)^2 = (x+2)^2 +297
(2x+1)^2=x^2+4x+4+297
4x^2+4x+1= x^2+4x+301
3x^2-300=0
3x^2=300
x^2=300/3
x^2=100
x=10
the integers are 10,11,12