SOLUTION: given that 1<x<4, write |x+7|-|x-9| without absolute value symbols. Is the answer 16?

Algebra ->  Absolute-value -> SOLUTION: given that 1<x<4, write |x+7|-|x-9| without absolute value symbols. Is the answer 16?      Log On


   



Question 318717: given that 1
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You may be tempted to think that abs%28x%29=x, but that is not true for all 'x'. It is only true if 'x' is positive. This is where you made a mistake. You're thinking that abs%28x-9%29=x-9, but with the given domain, this is not true.

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Recall that abs%28x%29=x if 'x' is positive. So abs%28x%2B7%29=x%2B7 if x%2B7%3E0. Solve for 'x' to get x%3E-7. Since 1%3Cx%3C4, this means that x%3E-7 is most certainly true and that abs%28x%2B7%29=x%2B7 is also true.


On the flip side, abs%28x%29=-x if x%3C0 (ie x is negative). Notice that abs%28x-9%29=-%28x-9%29 only because x-9%3C0 means that x%3C9 (which is certainly true since 1%3Cx%3C4). So once again abs%28x-9%29=-%28x-9%29


To recap, abs%28x%2B7%29=x%2B7 and abs%28x-9%29=-%28x-9%29. If this makes no sense at all why these two equations hold, just graph the two functions with the domain 1%3Cx%3C4. Let's now use this info to simplify the expression.

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abs%28x%2B7%29-abs%28x-9%29 Start with the given expression.


%28x%2B7%29-%28-%28x-9%29%29 Plug in abs%28x%2B7%29=x%2B7 and abs%28x-9%29=-%28x-9%29


x%2B7%2Bx-9 Negate the negative


2x-2 Combine like terms.


So abs%28x%2B7%29-abs%28x-9%29=2x-2 where 1%3Cx%3C4


So for example, if x=2, then abs%28x%2B7%29-abs%28x-9%29=abs%282%2B7%29-abs%282-9%29=abs%289%29-abs%28-7%29=9-7=2 and also 2x-2=2%282%29-2=4-2=2 which confirms that abs%28x%2B7%29-abs%28x-9%29=2x-2 when x=2. We can use other numbers in the domain 1%3Cx%3C4 to reconfirm our answer.


A better confirmation would be to graph y=abs%28x%2B7%29-abs%28x-9%29 and y=2x-2 to see that the two graphs match up completely over the domain 1%3Cx%3C4