SOLUTION: 3 red marbles,4 yellow marbles,and 2 green.. what are the odds in favor of selecting a red marble?

Algebra ->  Probability-and-statistics -> SOLUTION: 3 red marbles,4 yellow marbles,and 2 green.. what are the odds in favor of selecting a red marble?      Log On


   

Question 318587: 3 red marbles,4 yellow marbles,and 2 green.. what are the odds in favor of selecting a red marble?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
P(Red) = # of red marbles / # of marbles total = (3 red)/(3 red + 4 yellow + 2 green) = 3/9 = 1/3 = 0.333


So the probability is 1/3 which is a 33.33% chance