SOLUTION: how can i do to determinea ordered pair as solution of a system ex: x+2y^2=16 5x+6y=28

Algebra ->  Systems-of-equations -> SOLUTION: how can i do to determinea ordered pair as solution of a system ex: x+2y^2=16 5x+6y=28       Log On


   

Question 318561: how can i do to determinea ordered pair as solution of a system
ex:
x+2y^2=16
5x+6y=28






Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You're solving for the intersection of a parabola and a line.
.
.
.

.
.
.
You need to solve the system of equation simultaneously,
1.x%2B2y%5E2=16
2.5x%2B6y=28
From eq. 2,
5x=-6y%2B28
Multiply eq. 1 by 5 and substitute this expression.
5x%2B10y%5E2=80
-6y%2B28%2B10y%5E2=80
10y%5E2-6y-+52=0
%2810y-26%29%28y%2B2%29=0
Two solutions:
10y-26=0
10y=26
highlight%28+y=13%2F5+%29
then,
5x=-6%2813%2F5%29%2B28%2F5
5x=-78%2F5%2B140%2F5
5x=62%2F5
highlight%28x=62%2F25%29
(62%2F25,13%2F5)
.
.
.
y%2B2=0
highlight%28y=-2%29
then,
5x=-6%28-2%29%2B28
5x=12%2B28
5x=40
highlight%28x=8%29
(8,-2)
.
.
.