SOLUTION: The escape velocity v a spacecraft needs to leave the gravitational field of a planet varies directly as the square root of the product of the planet’s radius R and its accelera

Algebra ->  Trigonometry-basics -> SOLUTION: The escape velocity v a spacecraft needs to leave the gravitational field of a planet varies directly as the square root of the product of the planet’s radius R and its accelera      Log On


   

Question 318548: The escape velocity v a spacecraft needs to leave the gravitational field of a planet varies directly as the square root of the product of the planet’s radius R and its acceleration due to gravity g. For Mars and Earth:

Find for Mars if the escape velocity for earth,

Answer by Alan3354(69443) About Me  (Show Source):
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