SOLUTION: Complete the square and write the equation in standard form. Then give the center and radius of the circle. x^2 + y^2 + 16x - 2y = -29 Thanks

Algebra ->  Coordinate-system -> SOLUTION: Complete the square and write the equation in standard form. Then give the center and radius of the circle. x^2 + y^2 + 16x - 2y = -29 Thanks      Log On


   

Question 318526: Complete the square and write the equation in standard form. Then give the center and radius of the circle. x^2 + y^2 + 16x - 2y = -29
Thanks
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B16x%2B+y%5E2+-2y+=+-29
%28x%5E2+%2B16x%2B64%29%2B+%28y%5E2+-2y%2B1%29+=+-29%2B64%2B1
%28x%2B8%29%5E2%2B%28y-1%29%5E2=36
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It's a circle centered at (-8,1) with a radius of 6.