SOLUTION: An object is projected upward from the top of a tower. Its distance in feet above the ground after t seconds is given by s(t)=-16t^2+64t+80. How many seconds will it take to reach
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-> SOLUTION: An object is projected upward from the top of a tower. Its distance in feet above the ground after t seconds is given by s(t)=-16t^2+64t+80. How many seconds will it take to reach
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Question 31848This question is from textbook
: An object is projected upward from the top of a tower. Its distance in feet above the ground after t seconds is given by s(t)=-16t^2+64t+80. How many seconds will it take to reach ground level? This question is from textbook
You can put this solution on YOUR website! When it reaches ground level its height above the ground will be zero.
So, write -16t^2+64t+80=0
-16(t^2-4t+5)=0
(t-5)(t+1)=0
t=5 seconds or t=-1 second
The answer you want is t=5 seconds
Cheers,
Stan H.