SOLUTION: the two diagonals divide square ABCD into fours small triangles. What is the sum of the perimeters of those triangles?

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Question 318405: the two diagonals divide square ABCD into fours small triangles. What is the sum of the perimeters of those triangles?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

The perimeter of each triangle is,
Pt=s%2B2d
The total for 4 triangles would be,
P=4s%2B8d
d is related to the diagonal of the square,
D=d%2Bd=2d
D%5E2=s%5E2%2Bs%5E2=2s%5E2
D=sqrt%282%29%2As
Substituting,
P=4s%2B8d
P=4s%2B4D
P=4%28s%2Bsqrt%282%29s%29
highlight%28P=4s%281%2Bsqrt%282%29%29%29