SOLUTION: I am being asked to simplify the expression of i^29. Can you please help me with this? Thank you, Jerry jerry@san.rr.com

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I am being asked to simplify the expression of i^29. Can you please help me with this? Thank you, Jerry jerry@san.rr.com      Log On


   

Question 318268: I am being asked to simplify the expression of i^29. Can you please help me with this?
Thank you,
Jerry
jerry@san.rr.com
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
There is a pattern to the powers of i.
+i%5E%280%29=1+
i%5E%281%29=i
i%5E%282%29=-1
i%5E%283%29=i%5E%282%29%2Ai=-i
i%5E%284%29=%28i%5E%282%29%29%5E2=%28-1%29%5E2=1
i%5E%285%29=i%5E%284%29%2Ai=i
.
.
.
Now you only need to find out which one holds for 29
0,4,8,...=1
1,5,9,...=i
2,6,10,...=-1
3,7,11,...=-i