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Question 31826This question is from textbook Holt Algebra
: x squared+8x+16
This question is from textbook Holt Algebra
Answer by ikdeep(226)   (Show Source):
You can put this solution on YOUR website! x^2+8x+16.. ..........here x^2 means x squared..
We can solve it with two methods and these two methods are as follows..
First method:-
x^2+8x+16
It can also be written as ..
= (x)^2 + 2(x)4) + (4)^2
Here we apply the formula i.e (a)^2 + 2(a)(b)+ (b)^2 = (a+b)^2....
and here a = x ,,,b = 4....and we get..
= (x+4)^2
Second method:-
x^2+8x+16
Here you must know how we make factors i.e. splitting of the middle term...if you might not knew then contact me again and I will explain to you...we get...
= x^2+( 4 + 4)x + 16
on opening the brackets we get...
= x^2+ 4x + 4x + 16
taking common from first two i.e. x^2+ 4x and last two i.e. + 4x + 16
variables...we get
= x(x+4) + 4(x+4)
= (x+4)(x+4)
or it can also be written as
= (x+4)^2
hope this will help you
Please feel free to revert back for any further queries.
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