SOLUTION: hi i was wondering how u do elimination using mulitplication, its in ch. 13 in the algebra 1 book on systems of equations and inequalities, please help thank you. question number o

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Question 31802: hi i was wondering how u do elimination using mulitplication, its in ch. 13 in the algebra 1 book on systems of equations and inequalities, please help thank you. question number one is shown below.
2x+6y=10
5x+3y=1

Answer by mbarugel(146) About Me  (Show Source):
You can put this solution on YOUR website!
Hello!
In order to do elimination using multiplication, the idea is to multiply one of the equations by a given number so that the coefficients of either x or y are the same in both equations. Let me illustrate:
You have:
2x%2B6y=10
5x%2B3y=1
Look at the coefficients of x. In the 1st equation it's 2; in the second one it's 5. You could multiply the first equation by 2.5 and you would get another 5 as the x coefficient in it. The first equation would become:
2x%2B6y=10
2.5%282x%2B6y%29=2.5%2810%29
5x+%2B+15y+=+25
And the nyou would be ready to eliminate. Just subtract the 2nd equation from the 1st one, getting:
+%285x+-+5x%29+%2B+%2815y+-+3y%29+=+25+-+1
+0+%2B+12y+=+24
12y+=+24
And now it's easy to find the value of y; and afterwards, of x.

In the example I showed you, I did a multiplication such that the x would 'disappear' after the subtraction. Of course, you could have done the same with y instead of x. The original system was:
system%282x%2B6y=10%2C5x%2B3y=1%29
Look at the coefficients of y: 6 in the 1st equation and 3 in the 2nd one. If you multiplied the 2nd equation by 2, you would get a '6y' in it. Let's do it:
2%2A%285x%2B3y%29=2%2A1
10x%2B6y+=+2
And then you could subtract the 1st equation from this one, getting:
%2810x-2x%29+%2B+%286y+-+6y%29+=+2+-+10
8x+%2B+0+=+-8
8x+=+-8
So now we can easily find x, and then y by simple subtitution.

I hope this helps!
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