SOLUTION: The length of a rectangle is 19 feet longer than the width If the perimeter is 46 feet, what are the dimensions of the rectangle

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Question 317744: The length of a rectangle is 19 feet longer than the width If the perimeter is 46 feet, what are the dimensions of the rectangle
Answer by texttutoring(324) About Me  (Show Source):
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Let l = length
Let w = width
Let P = perimeter
Two Equations, one for length, one for Perimeter:
l = 19+w
P = 2w + 2l

Substitute l=19+w and P = 46 into the Perimeter equation and solve for w:

P = 2w + 2l
46 = 2w + 2(19+w)
46 = 2w + 38 +2w
46 = 4w + 38
8 = 4w
w = 2

l=19+w
l = 19 + 2
l = 21

The width is 2 feet, and the length is 21 feet.