SOLUTION: I tried to solve this: Find h(f(x)) if h(x)=1/(x+2) and f(x)=4x-3 Please confirm my answer is correct: h(f(x))=h(y) f(x)=y 1/x+2 = 1/y+2 1/sqrt(2x+3)+2 Thanks in advan

Algebra ->  Expressions -> SOLUTION: I tried to solve this: Find h(f(x)) if h(x)=1/(x+2) and f(x)=4x-3 Please confirm my answer is correct: h(f(x))=h(y) f(x)=y 1/x+2 = 1/y+2 1/sqrt(2x+3)+2 Thanks in advan      Log On


   

Question 31765: I tried to solve this:
Find h(f(x)) if h(x)=1/(x+2) and f(x)=4x-3
Please confirm my answer is correct:
h(f(x))=h(y)
f(x)=y
1/x+2 = 1/y+2
1/sqrt(2x+3)+2
Thanks in advance for your help.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
h[f(x)]=h[4x-3]= 1/[(4x-3)+2]= 1/(4x-1)
Cheers,
stan H.