SOLUTION: Hello:
Here is the problem I am working on:
f(x)=x^4+13x^2+36
I am to find the complex zeros. I found -5 (x+5). But, if I were to divide the factor into the equation, I
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-> SOLUTION: Hello:
Here is the problem I am working on:
f(x)=x^4+13x^2+36
I am to find the complex zeros. I found -5 (x+5). But, if I were to divide the factor into the equation, I
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Question 31755This question is from textbook
: Hello:
Here is the problem I am working on:
f(x)=x^4+13x^2+36
I am to find the complex zeros. I found -5 (x+5). But, if I were to divide the factor into the equation, I don't get a quadratic equation, so I cannot use the quad formula. Any help appreciated.
Thanks,
Brad Olson This question is from textbook
You can put this solution on YOUR website! IF IT IS A QUADRATIC YOU CAN DO...SO CONVERT IT INTO A QUADRATIC..PUT Y=X^2..SO WE GET
f(x)=x^4+13x^2+36=Y^2+13Y+36...IT IS A QUADRATIC...FIND Y ...THEN TAKE SQUARE ROOT TO FIND X...IF STILL IN DIFFICULTY PLEASE COME BACK
