SOLUTION: Solve the nonlinear system of equations. 3x2 + y2 = 3 4x2 + 5y2 = 26 Thanks!!!

Algebra ->  Equations -> SOLUTION: Solve the nonlinear system of equations. 3x2 + y2 = 3 4x2 + 5y2 = 26 Thanks!!!      Log On


   



Question 31741: Solve the nonlinear system of equations.
3x2 + y2 = 3
4x2 + 5y2 = 26
Thanks!!!

Found 2 solutions by checkley71, ikdeep:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
3X~2+Y~2=3
4X~2+5Y~2=26 MULTIPLYING THE FIRST EQUATION BY -5 WE GET
-15X~2-5Y~2=-15 ADDING THIS TO THE SECOND EQUATION
4X~2+5Y~2=26 WE GET
-11X~2=11 OR X~2=-1 SUBSTITUTING THIS IN THE SECOND EQUATION WE GET
4(-1)+5Y~2=26 OR -4+5Y~2=26 OR 5Y~2=30 OR Y~2=30/6 OR Y~2=6
PROOF 3(-1)+6=3 OR -3+6=3 OR 3=3 AND
4(-1)+5(6)=26 OR -4+30=26 OR 26=26

Answer by ikdeep(226) About Me  (Show Source):
You can put this solution on YOUR website!
3x2 + y2 = 3 ..................(1)
4x2 + 5y2 = 26..................(2)
You can solve it by elimination method (equating the coefficient )
To equate the coefficient of y^2,,,multiply (1) by 5 and we get...
15x2 + 5y2 = 15 ..................(3)
Subtract (2) from (3)..we get
15x2 + 5y2 = 15
4x2 + 5y2 = 26
- - -
------------------
11x2 = -11 (here 5y2 would be eliminated from both equation.)
divide both sides by 11 and we get ...
x2 = -1
now put this value of x either in (1)or in(2),,you get the same value of y2 ,,here I am taking (1)...and we get
3(-1) + y2 = 3
opening brackets would give ...
-3 + y2 = 3
add 3 on both sides and we get....
y2 = 6
Now if you want to verify you answer ,,,you can put the values of x and y in any of the equation and if you get LHS = RHS,,,this means that you answer is correct..
hope this will help you
Please feel free to revert back for any further queries.