SOLUTION: Hi all, I was hoping someone would show me how to Find the scalar products of the vectors: a = i - j + 3k and b = -i + 2j + k What can be said about the position of these ve

Algebra ->  Vectors -> SOLUTION: Hi all, I was hoping someone would show me how to Find the scalar products of the vectors: a = i - j + 3k and b = -i + 2j + k What can be said about the position of these ve      Log On


   

Question 317065: Hi all,
I was hoping someone would show me how to Find the scalar products of the vectors: a = i - j + 3k and b = -i + 2j + k
What can be said about the position of these vectors relative to eachother?
How can I determine a + b?
Some help with relavant steps and explanations would be great.
-Nick.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
a=(1,-1,3)
b=(-1,2,1)
a.b=1%28-1%29%2B%28-1%29%282%29%2B3%281%29=-1-2%2B3=0
Since the dot product is zero, the vectors are perpendicular to each other.
.
.
Add the vectors component by component.
a+b=(1,-1,3)+(-1,2,1)=(1-1,-1+2,3+1)=(0,1,4)