SOLUTION: How do you write the expression 2 ln x-4 ln (1/y) - 3 ln (xy) as one logarithm?

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Question 317034: How do you write the expression 2 ln x-4 ln (1/y) - 3 ln (xy) as one logarithm?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do you write the expression 2 ln x-4 ln (1/y) - 3 ln (xy) as one logarithm?
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2ln(x) -4ln(1/y) - 3ln(xy)
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= ln(x^2) - 4[ln(1)-ln(y)] - ln(xy)^3
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= ln(x^2) - 4[-ln(y)] - ln(xy)^3
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= ln(x^2) + 4ln(y) - ln(xy)^3
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= ln(x^2) + ln(y^4) - ln(xy)^3
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= ln[x^2*y^4/(x^3*y^3)]
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= ln[y/x]
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Cheers,
Stan H.
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