Question 317029: Can someone please help me get this problem finished or should I say help me with it. I am totally drawing a blank.
A randomly selected sample of n = 51 men in Brazil had an average lifespan of 59 years. The standard deviation was 10 years, and the standard error of the mean is 1.400. Calculate a 90% confidence interval for the average lifespan for all men in Brazil.
1) (56.6, 61.4)
2)(42.2, 75.8)
3) (56.2, 61.8)
Kristal
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A randomly selected sample of n = 51 men in Brazil had an average lifespan of 59 years. The standard deviation was 10 years, and the standard error of the mean is 1.400. Calculate a 90% confidence interval for the average lifespan for all men in Brazil.
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x-bar = 59
ME = (invT(0.05 with df = 50)*SE
ME = (1.6759)1.4 = 2.3463
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90% CI: 59-2.3463 < u < 59+2.3463
90% CI: 56.65 < u < 61.35
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Cheers,
Stan H.
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1) (56.6, 61.4)
2)(42.2, 75.8)
3) (56.2, 61.8)
Kristal
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