SOLUTION: Solve the following system of equations x-2y=-8 3x+2y=0 (x,y)=?
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Question 316828
:
Solve the following system of equations
x-2y=-8
3x+2y=0
(x,y)=?
Answer by
checkley77(12844)
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x-2y=-8
3x+2y=0 add.
--------------
4x=-8
x=-8/4
x=-2 ans.
-2-2y=-8
-2y=-8+2
-2y=-6
y=-6/-2
y=3 ans.
Proof:
3*-2+2*3=0
-6+6=0
0=0