SOLUTION: The diameter of a pipe is normally distributed with a mean of 0.4 inch and a variance of 0.0004. What is the probability that the diameter of a randomly selected pipe will exceed

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Question 316597: The diameter of a pipe is normally distributed with a mean of 0.4 inch and a variance of 0.0004. What is the probability that the diameter of a randomly selected pipe will exceed 0.44 inch? Express your answer as a percen to two decimal places.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Variance=0.0004
Standard deviation is the square root of variance.
sigma=sqrt%280.0004%29=0.02
Find the z score for 0.44 inches.
z=%280.44-0.4%29%2F0.02=2
P(x<=0.44)=P%282%29=0.97725
P(x>0.44)+P(x<=0.44)=1
P(x>0.44)=1-P(x<=0.44)
P(x>0.44)=1-0.97725
P(x>0.440=0.02275