SOLUTION: (6z^2+36z+54)/(z^2-3z-18)

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Question 316293: (6z^2+36z+54)/(z^2-3z-18)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%286z%5E2%2B36z%2B54%29%2F%28z%5E2-3z-18%29 Start with the given expression.


%286%28z%2B3%29%28z%2B3%29%29%2F%28z%5E2-3z-18%29 Factor the numerator.


%286%28z%2B3%29%28z%2B3%29%29%2F%28%28z-6%29%28z%2B3%29%29 Factor the denominator.


Highlight the common terms.


%286%28z%2B3%29%2Across%28%28z%2B3%29%29%29%2F%28%28z-6%29%2Across%28%28z%2B3%29%29%29 Cancel out the common terms.


%286%28z%2B3%29%29%2F%28z-6%29 Simplify.


%286z%2B18%29%2F%28z-6%29 Distribute.


So %286z%5E2%2B36z%2B54%29%2F%28z%5E2-3z-18%29 simplifies to %286z%2B18%29%2F%28z-6%29


In other words, %286z%5E2%2B36z%2B54%29%2F%28z%5E2-3z-18%29=%286z%2B18%29%2F%28z-6%29