SOLUTION: Hi. I need to express the logarithmic expression: logsuba((xsqrta)/y^2)) in terms of x and y. I know that when expanding logs, division becomes subtraction; so this would be

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hi. I need to express the logarithmic expression: logsuba((xsqrta)/y^2)) in terms of x and y. I know that when expanding logs, division becomes subtraction; so this would be      Log On


   

Question 316267: Hi. I need to express the logarithmic expression:
logsuba((xsqrta)/y^2)) in terms of x and y.
I know that when expanding logs, division becomes subtraction; so this would be:
logsubaXsqrta - 2logsubaY .
The part I need help understanding is how to get rid of the sqrta in order to get the answer:
logsubaX - 2logsubaY + 1/2
If you can help, it would be much appreciated! Thanks!
~hbanana
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Since sqrt%28a%29+=+a%5E%281%2F2%29=Log%5Ba%5D%28x%29%2BLog%5Ba%5D%28a%5E%281%2F2%29%29-Log%5Ba%5D%28y%5E2%29 Now apply the power rule to get:
Log%5Ba%5D%28x%29%2B%281%2F2%29Log%5Ba%5D%28a%29-2Log%5Ba%5D%28y%29 but Log%5Ba%5D%28a%29+=+1, so...