SOLUTION: you are given a two-digit positive integer . if you reverse the digits of your number, the result is a number which is 20% larger than your number . what is your number ?

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: you are given a two-digit positive integer . if you reverse the digits of your number, the result is a number which is 20% larger than your number . what is your number ?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 316149: you are given a two-digit positive integer . if you reverse the digits of your number, the result is a number which is 20% larger than your number . what is your number ?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
you are given a two-digit positive integer .
if you reverse the digits of your number, the result is a number which is 20% larger than your number .
what is your number ?
:
Let 10x + y = "the number
then
10y + x = the reversed number
:
1.2(10x+y) = 10y + x
:
12x + 1.2y = 10y + x
12x - x = 10y - 1.2y
11x = 8.8y
divide both sides by 11
x = .8y
The only single digit value for y that will give an integer value to x, is 5
.8(5) = 4
the digits:
x=4, y=5
45 is the number (54 is the reversed number)
:
:
Check: 54/45 = 1.2