SOLUTION: A ball is thrown upward with an initial velocity of 32 ft/sec from a height of six feet. The function s(t)=-16t^2+32t+6 gives the height of the ball t seconds after release. Determ
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Question 316048: A ball is thrown upward with an initial velocity of 32 ft/sec from a height of six feet. The function s(t)=-16t^2+32t+6 gives the height of the ball t seconds after release. Determine the time when the ball is at maximun height, and find that height. Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! s(t) is a downward opening parabola ("a" is negative) ; so the maximum is at the vertex , which is on the axis of symmetry
