SOLUTION: The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 cm2, find the dimensions of the rectangle. Enter your answers in the blanks. Ent

Algebra ->  Sequences-and-series -> SOLUTION: The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 cm2, find the dimensions of the rectangle. Enter your answers in the blanks. Ent      Log On


   

Question 315979: The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 cm2, find the dimensions of the rectangle. Enter your answers in the blanks. Enter only the numeric values rounded to the nearest thousandth of a centimeter.
Width = __________cm, Length = _________cm.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
L=2W+3
A=LW
93=(2W+3)W
93=2W^2+3W
2W^2+3W-93=0
W+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
W=(-3+-SQRT93^3-4*2*-93])/2*2
W=(-3+-SQRT[9+744])/4
W=(-3+-SQRT753)/4
W=(-3+-27.44)/4
W=(-3+27.44)/4
W=24.44/4
W=6.11 ANS. FOR THE WIDTH.
L=2*6.11+3=12.22+3=15.22 ANS. FOR THE LENGTH.
PROOF:
93=15.22*6.11
93~93