SOLUTION: log (base 3)(x+9) -log(base 3)x=3 Show me, how to do this problem, so i get it :D
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Question 315788
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log (base 3)(x+9) -log(base 3)x=3
Show me, how to do this problem, so i get it :D
Answer by
scott8148(6628)
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subtracting logs means dividing quantities
log3[(x+9) / x] = 3
3^3 = 27 , so ___ log3[(x+9) / x] = log3(27)
removing logs ___ (x+9) / x = 27
multiplying by x ___ x + 9 = 27x ___ 9 = 26x ___ 9/26 = x