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Question 315531: please help me solve this question:
y^2+2y=x^2+x
is this equation a parabola, circle, ellipse, or hyperbola? how do you know?
thnks
Found 2 solutions by Edwin McCravy, stanbon: Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website! please help me solve this question:
y2 + 2y = x2 + x
is this equation a parabola, circle, ellipse, or hyperbola? how do you know?
thnks
Get it in the standard conic form:
Ax2 + Bxy + Cy2 + Dx + Ey + F = 0
then calculate the discriminant, which is B2 - 4AC
1. If the discriminant is positive, the equation represents a hyperbola.
2. If the discriminant is zero, the equation represents a parabola.
3. If the discriminant is negative then it is either an ellipse or a circle.
If it's a circle, then B=0 and A=C, otherwise it's an ellipse.
So let's get
y2 + 2y = x2 + x
in the standard conic form
Ax2 + Bxy + Cy2 + Dx + Ey + F = 0
Get 0 on the right by subtracting the right side from both sides:
y2 + 2y - x2 - x = 0
Now lets rearrange the terms in the order as they appear in the standard
conic form:
Ax2 + Bxy + Cy2 + Dx + Ey + F = 0
-1x2 + 0xy + 1y2 - 1x + 2y + 0 = 0
So A=-1, B=0, C=1, D=-1, E=2, F=0
B2 - 4AC = (0)^2 - 4(-1)(1) = 0 - (-4) = 0 + 4 = 4
That's positive, so the equation represents a hyperbola.
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Edwin
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! y^2+2y=x^2+x
is this equation a parabola, circle, ellipse, or hyperbola? how do you know?
It is a hypobola because the x^2 and y^2 have opposite signs when
arranged on the same side of the equation.
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Rearrange:
x^2 + x - (y^2+2y) = 0
Complete the square:
(x^2 + x + (1/2)^2) - (y^2+2y+1) = (1/2)^2 - 1
(x+1/2)^2 - (y+1)^2 = -3/4
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(y+1)^2 - (x+(1/2))^2 = (3/4)
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Cheers,
Stan H.
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