SOLUTION: A launched rocket has an altitude in meters, given by the polynomial h+vt-4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for
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-> SOLUTION: A launched rocket has an altitude in meters, given by the polynomial h+vt-4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for
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Question 315516: A launched rocket has an altitude in meters, given by the polynomial h+vt-4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for which it takes the rocket to become airborne. If the rocket is launched from the top of a tower that is 120 meters and the initial speed is 50 meters per second, what will its height be after 4 seconds rounded to the nearest tenth? Answer by nyc_function(2741) (Show Source):
You can put this solution on YOUR website! Let capital H = height after 4 seconds
H = h + vt - (4.9^(2))
H = 120 + (50)(4) - (4.9^(2))
H = 320 - (4.9^(2))
H = 320 - 24.01
H = 295.99 meters.
After rounding = 296 meters.
