SOLUTION: Find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer      Log On


   

Question 315412: Find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer
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1st 2x-2
2nd 2x
3rd 2x+2
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Equation:
(2x)(2x+2) = 10(2x-2)+20
4x^2 + 4x = 20x-20+20
4x^2+4x= 20x
4x^2-16x = 0
4x(x-4) = 0
x = 0 or x = 4
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To get positive even integers let x = 4:
1st: 2x-2 = 6
2nd: 2x = 8
3rd: 2x+2 = 10
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Cheers,
Stan H.