SOLUTION: Mike has $1.55 in dimes and nickles. if he has 7 more nickels than dimes, how many of each coin does he have?

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Question 31538: Mike has $1.55 in dimes and nickles. if he has 7 more nickels than dimes, how many of each coin does he have?

Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
Let the dimes be x
Let the nickels be x+7
Equation:
0.05(x+7)+0.1x=1.55
0.05x+0.35+0.1x=1.55
0.15x=1.2
x=8
8+7=15

Hence, their are 15 nickels and 15 dimes.
PAul.