SOLUTION: find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer      Log On


   

Question 315365: find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let the first integer be x
second = x+2
third = x+4
..
(x+2)(x+4)=10x+20
x^2+6x+8=10x+20
x^2-4x-12=0
x^2-6x+4x-12=0
x(x-6)+4(x-3)=0
(x-6)(x+4)=0
x= 6
the numbers are 6,8,10.