SOLUTION: evaluate the logarithm. 1. log (base 7) 1/49 write the expression as a single logarithm 2. 5log (base b)q+3 log(base b)w 3. 4 log x-6 log (x+2) 4. solve 4^2x=111

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: evaluate the logarithm. 1. log (base 7) 1/49 write the expression as a single logarithm 2. 5log (base b)q+3 log(base b)w 3. 4 log x-6 log (x+2) 4. solve 4^2x=111      Log On


   

Question 315262: evaluate the logarithm.
1. log (base 7) 1/49
write the expression as a single logarithm
2. 5log (base b)q+3 log(base b)w
3. 4 log x-6 log (x+2)
4. solve 4^2x=111
Found 2 solutions by nerdybill, MathTherapy:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
1. log (base 7) 1/49
+log%287%2C1%2F49%29+
+log%287%2C1%29-+log%287%2C49%29+
+log%287%2C7%5E0%29-+log%287%2C7%5E7%29+
+0-7+
+-7+

write the expression as a single logarithm
2. 5log (base b)q+3 log(base b)w
5log%28b%2Cq%2B3%29log%28b%2Cw%29
log%28b%2C%28q%2B3%29%5E5%29log%28b%2Cw%29
log%28b%2C%28q%2B3%29%5E5%2Bw%29
3. 4 log x-6 log (x+2)
4+log%28x%29+-+6log%28x%2B2%29
log%28x%5E4%29+-+log%28%28x%2B2%29%5E6%29
log+%28x%5E4%2F%28x%2B2%29%5E6%29
4. solve 4^2x=111
4%5E%282x%29=111
log%284%2C4%5E%282x%29%29=+log%284%2C111%29
2x=+log%284%2C111%29
x=+log%284%2C111%29%2F2
x=+log%28111%29%2F2log%284%29
x=+1.7

Answer by MathTherapy(10699) About Me  (Show Source):
You can put this solution on YOUR website!
evaluate the logarithm.
1. log (base 7) 1/49

write the expression as a single logarithm

2. 5log (base b)q+3 log(base b)w

3. 4 log x-6 log (x+2)

4. solve 4^2x=111
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evaluate the logarithm.
1. log (base 7) 1/49
The answer, - 7, according to the person who responded, is WRONG!

1. log (base 7) 1/49
log%287%2C+1%2F49%29+=+log+%287%2C+%287%5E%28-+2%29%29%29 
It's actually - 2 ---- log+%28b%2C+%28b%5Ea%29%29+=+a applied
*********************************
write the expression as a single logarithm 
2. 5log (base b)q+3 log(base b)w 
If this is 5%2Alog%28b%2C+%28q%29%29+%2B+3%2Alog%28b%2C+%28w%29%29 i/o 5%2Alog%28b%2C+%28q+%2B+3%29%29+%2A+log%28b%2C+%28w%29%29, then the other person's answer, log%28b%2C+%28q+%2B+3%29%5E5+%2B+w%29, is WRONG! 
           5%2Alog%28b%2C+%28q%29%29+%2B+3%2Alog%28b%2C+%28w%29%29
           log%28b%2C+%28q%5E5%29%29+%2B+log%28b%2C+%28w%5E3%29%29
And finally, log%28b%2C+%28q%5E5w%5E3%29%29