SOLUTION: A bicycle leaves town at 10mph at 8am and a car leaves at 11am, traveling in the same direction at 50mph. How many minutes after 11am will it be when the car overtakes the bike?

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Question 315240: A bicycle leaves town at 10mph at 8am and a car leaves at 11am, traveling in the same direction at 50mph. How many minutes after 11am will it be when the car overtakes the bike?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
D=10T FOR THE CYCLIST
D=50(T-3)
10T=50(T-3)
10T=50T-150
10T-50T=-150
-40T=-150
T=-150/-40
T=3.75 HOURS AFTER 8 AM THEY WILL MEET.
8:00+3:45=11:45 OR 11:45 THE CAR WILL OVERTAKE THE CYCLIST.