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| Question 315055:  How to find the equation of the line tha contains the point (-1, 4) and is parallel to the line 2x - 3y = 5.
 I can get the slope of the given line.  But i am getting lost using the point slope formula once I get to y -4 = 2/3x + 2/3.  Could you please work through the entire equation without leaving any step out please.. Thank you so much
 Grateful
 Sandy
 Found 2 solutions by  Alan3354, rapaljer:
 Answer by Alan3354(69443)
      (Show Source): 
You can put this solution on YOUR website! How to find the equation of the line tha contains the point (-1, 4) and is parallel to the line 2x - 3y = 5. I can get the slope of the given line. But i am getting lost using the point slope formula once I get to y -4 = 2/3x + 2/3. Could you please work through the entire equation without leaving any step out please.. Thank you so much
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 y -4 = 2/3x + 2/3
 You can add 4 to both sides to get y = (2/3)x + 14/3, but it's not necessary.  The slope is 2/3, that's all you need to know.
 Parallel lines have the same slope.
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 Use y = mx + b and the point to find b.
 4 = (2/3)*-1 + b
 b = 4 - 2/3 = 10/3
 Now you have m and b
 --> y = (2/3)x + 10/3
 
Answer by rapaljer(4671)
      (Show Source): 
You can put this solution on YOUR website! The solution offered by the OTHER tutor has an error.  Where he attempted to solve for b=4-2/3, it should have been b=4+2/3, which would have given a final answer of y=2/3 x + 14/3, NOT 10/3 !! 
 Dr. Robert J. Rapalje, Retired
 
 
 If you got to the part of the problem where you had
 
   
 Next, I recommend clearing the fraction by multiplying both sides by 3:
 
   
 Finally, in order to get x and y terms on the same side with a positive x coefficient, I would subtract 3y from each side:
 
   
 Bring the numbers to the left side by subtracting 2 from each side:
 
  or   
 As a check, you may want to plug in the (-1,4) to see if it works:
 2x-3y=-14
 2(-1)-3(4)=-14
 -2-12=-14
 It checks.
 
 Dr. Robert J. Rapalje, Retired
 Seminole State College of Florida
 Altamonte Springs Campus
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