Question 315052: Factor completely.
6x^2 + 8x + 2
I do not understand how to get this, but the answer in the back of the book is 2(3x + 1)(x +1)
Found 2 solutions by Alan3354, rapaljer:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Factor completely.
6x^2 + 8x + 2
All the coefficients are even, so factor out a 2
= 2*(3x^2 + 4x + 1)
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The middle coefficient is the sum of the other 2.
= 2(3x+1)*(x+1)
Answer by rapaljer(4671)  (Show Source):
You can put this solution on YOUR website! This problem requires TWO steps. You are probably trying to do it in one step, and it just can't be done!
Step 1: Factor the COMMON FACTOR, which is 2:
2(3x^2 +4x+1)
Step 2: Factor the TRINOMIAL. I call this particular problem "Advanced Trinomial Factoring", since the coefficient of x^2 is greater than 1. It looks like this:
2(____)(____)
The FIRST times FIRST has to be 3x*x, and the LAST times LAST has to be 1*1:
2(3x+1)(x+1)
For additional explanation of FACTORING, please visit my own website by clicking on my tutor name "rapaljer" anywhere in algebra.com. Click on the link that is there to the Homepage of my website, and look for the link "Basic, Intermediate, and College Algebra: One Step at a Time." Click on "Basic Algebra", "Chapter 2". For "Factoring the Common Factor", see Section 2.03. For "Trinomial Factoring", see Section 2.04, and for "Advanced Trinomial Factoring" see Section 2.06. See also the "Math in Living Color" pages where problems from these sections are explained IN COLOR.
A few years before I retired, we recorded videos on some of the most important and troublesome topics in algebra. These videos are now available FREE from the website. From the Homepage, look for the link "Rapalje Videos in Living Color. For an explanation of FACTORING, in "Basic Algebra" OR in "Intermediate Algebra", click on "Factoring".
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
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