SOLUTION: Suppose a population of initial size 100 grows at the rate of 8% per year forever.
What is the size of the population at the end of year 1?
What is the size of the population at
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-> SOLUTION: Suppose a population of initial size 100 grows at the rate of 8% per year forever.
What is the size of the population at the end of year 1?
What is the size of the population at
Log On
Question 314750: Suppose a population of initial size 100 grows at the rate of 8% per year forever.
What is the size of the population at the end of year 1?
What is the size of the population at the end of year 2?
What is the size of the population at the end of year 3?
what is the size of the population at the end of year n (for any integer n)?
What algebraic equation would you need to solve to find the number of years x that it would take for our population to reach 200 Answer by Jstrasner(112) (Show Source):
You can put this solution on YOUR website! hey,
Well the initial equation would be:
S(size)n=100(1.08^n)
So for the first year:
S1= 100(1.08^1)= 108 people
S2= 100(1.08^2)= 116.64 => so 117 people roughly
S3= 100(1.08^3)= 125.97 => so 126 people roughly
As shown above the size at n years is :
100(1.08^n)
As for the algebraic equation:
we would use the one above:
200 = 100(1.08^n)
and you would use log
I hope this helps!
