SOLUTION: one side of a right triangle is 8 cm and the difference between other two sides is 4 cm. find its area by heron’s formula.
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Question 314727: one side of a right triangle is 8 cm and the difference between other two sides is 4 cm. find its area by heron’s formula. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! one side of a right triangle is 8 cm and the difference between other two sides is 4 cm. find its area by heron’s formula.
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using Pythagoras theorem
let hyp = x
side1 = x-4
side 2 = 8
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x^2= (x-4)^2+64
x^2=x^2-8x+16+64
8x=16+64
8x=80
x=10 cms
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side 1 = 8 cm.
side 2 = 10 cm.
side 3 = 10-4 cm.=6cm
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area = sqrt(s(s-a)(s-b)(s-c))
s= 10+8+6 /2
s=24 /2
s= 12
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Area = sqrt{12(12-8)(12-10)(12-6)
Area = sqrt{12(4)(2)(6)}
Area = sqrt{576}
Area = 24 sq. cm.
