SOLUTION: The sum of the two digits of a number is 16. The number formed be reversing the digits is 18 more than the original number. Determine the original number.
Let t= the tens digit,
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Let t= the tens digit,
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Question 314696: The sum of the two digits of a number is 16. The number formed be reversing the digits is 18 more than the original number. Determine the original number.
Let t= the tens digit, u= the units digit, and u+t=16. What equation would complete the system? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! 1....t+u=16
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the number is 10t+u
if this is reversed it becomes 10u+t
this is 18 more than the original number
..
10u+t = 10t+u+18
9u-9t=18
2....u-t=2
Add equation1 & 2
t+u+u-t=16+2
2u=18
u=9
so t= 7
The number = 97