SOLUTION: The length of a rectangle is 6 yards longer than its width.
If the perimeter of the rectangle is 52 yards find its area.
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-> SOLUTION: The length of a rectangle is 6 yards longer than its width.
If the perimeter of the rectangle is 52 yards find its area.
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Question 314657: The length of a rectangle is 6 yards longer than its width.
If the perimeter of the rectangle is 52 yards find its area. Answer by Jstrasner(112) (Show Source):
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So for this one, we simply need to write what we know down:
for the perimeter:
2L + 2W = 52 yards
for the info:
L = W + 6
We can substitute L in the equation for W + 6:
2(W+6) + 2W =52
2W + 12 + 2W =52
4W + 12 = 52
4W = 40
W = 10
then we subsitute W into the original equation:
L = 10 + 6
L = 16
Area is length multiplied by width:
A=L*W
Therefore:
A= 16*10 => 160 yards^2
