SOLUTION: In the morning, May drove to an appointment at 50 mph. Her average speed on the return trip in the afternoon was 40 mph. The return trip took 1/5 hour longer. How far did she trave
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: In the morning, May drove to an appointment at 50 mph. Her average speed on the return trip in the afternoon was 40 mph. The return trip took 1/5 hour longer. How far did she trave
Log On
Question 314531: In the morning, May drove to an appointment at 50 mph. Her average speed on the return trip in the afternoon was 40 mph. The return trip took 1/5 hour longer. How far did she travel to the appointment? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! D=RT
D=50T
D=40(T+.2)
50T=40(T-.2)
50T=40T+.8
50T-40T=8
10T=8
T=8/10
T=.8 HOURS OR 48 MINUTES.
50*.8=40 MILES IS THE DISTANCE.
40(.8+.2)=40*1=40 MILES.