SOLUTION: 3) A regular hexagon is inscribed in a circle with circumference of 16π. A second circle is inscribed inside the hexagon. If you pick a point at random inside the larger circ

Algebra ->  Probability-and-statistics -> SOLUTION: 3) A regular hexagon is inscribed in a circle with circumference of 16π. A second circle is inscribed inside the hexagon. If you pick a point at random inside the larger circ      Log On


   

Question 31446: 3) A regular hexagon is inscribed in a circle with circumference of 16π. A second circle is inscribed inside the hexagon. If you pick a point at random inside the larger circle, what is the probability that the point is also in the area of the smaller circle?
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
CIRCUMFERENCE OF OUTER CIRCLE =16*PI
DIAMETER=16*PI/PI=16...........RADIUS =8
AREA=8*8*PI=64*PI
INSCRIBED CIRCLE WILL HAVE ITS RADIUS EQUAL TO ALTITUDE OF ANY EQUILATERAL TRIANGLE FORMED BY ONE SIDE OF HEXAGON WITH CENTRE OF BIG CIRCLE.
SIDE OF HEXAGON = RADIUS OF CIRCUM CIRCLE =8
ALTITUDE = 8 *SIN60=8*SQRT.(3)/2=4SQRT.3
SO AREA OF INNER CIRCLE=PI*4*4*(SQRT.3)^2=48*PI
SO PROBBILITY OF A RANDOM POINT SELECTED IN BIG CIRCLE WILL FALL IN THE SMALLER CIRCLE=AREA OF SMALL CIRCLE/AREA OF BIG CIRCLE= 48*PI/64*PI=3/4=0.75