SOLUTION: Find the vertex and the axis of symmetry for the parabola y=2x^2+8x+5.

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Question 314436: Find the vertex and the axis of symmetry for the parabola y=2x^2+8x+5.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square to get the equation into vertex form,
y=a%28x-h%29%5E2%2Bk
.
.
.
y=2%28x%5E2%2B4x%29%2B5
y=2%28x%5E2%2B4x%2B4%29%2B5-8
y=2%28x%2B2%29%5E2-3
The vertex is (-2,-3).
The axis of symmetry is x=-2.