Question 314409: 
Hello, can you please help me solve this?
Found 3 solutions by mananth, rapaljer, Jstrasner:
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! {{(1/x) + (1/(1+x)) = ((-3)/(x^2+x)
{{(1/x) + (1/(1+x)) = ((-3)/x(x+1))
{(1/x) + (1/(1+x)) +(3/x(x+1)=0
LCM = x(x+1)
x+1 +x +3 / x(x+1)=0
2x+4=0
2x=-4
x=-2
Answer by rapaljer(4671)  (Show Source):
You can put this solution on YOUR website! First, factor the third denominator into x(x+1). Then realize that the LCD is x(x+1). Now, multiply both sides of the equation by x(x+1).
Finally, check each denominator to make sure that when x=-2, no denominators are equal to zero.
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Also, I have a video called "Fractional and Literal Equations" that was made a few years ago in one of my classrooms, that can be viewed from my website FREE. To see the videos look on my Homepage for the link "Rapalje Videos in Living Color." Choose "Intermediate Algebra". Let me know if they help, or if you have questions--my Email address is at the bottom of each page of my website. Math is usually not as hard as it looks!!
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Seminole State College of Florida
Altamonte Springs Campus
Answer by Jstrasner(112)  (Show Source):
You can put this solution on YOUR website! Hey,
This shouldn't be too difficult.
So first all of the denominators have to be the same. So we must multiply each expression by something ont he top and bottom to get the same denominator.
Therefore:
the greatest common denominator is (x^2)+x
Therefore you need to multiply (1/x) by (1+x/1+x) so that the denominator is (x^2+x). You will get (1+x)/((x^2)+x) for the first expression.
For the second : 1/(1+x), you need to multiply the top and the bottom by x to get:
x/((x^2)+x)
Now that all of the expressions have the same denominator, we can change the equation to:
(1+x)+x=-3
And from here we get:
1+2x=-3 => 2x=-4 => x=-2
I hope this helps!
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