SOLUTION: Please help! I have to get this done.
Simplify (if possible).
a) I was having trouble getting this one to display the right way so I just typed it out normally. I hope you ca
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Expressions-with-variables
-> SOLUTION: Please help! I have to get this done.
Simplify (if possible).
a) I was having trouble getting this one to display the right way so I just typed it out normally. I hope you ca
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Question 314336: Please help! I have to get this done.
Simplify (if possible).
a) I was having trouble getting this one to display the right way so I just typed it out normally. I hope you can still understand it.
2x/2x^2-7x+3 - x/x^2-9
b) Answer by Jstrasner(112) (Show Source):
You can put this solution on YOUR website! Hey
So if I read this right:
(2x/2x^2)-7x+3-(x/x^2)-9
The great thing about having the same expressions (x, y, z) in the numerator and int he denominator is that you can cancel them out to some extent. Therefore:
the first expression (2x/2x^2) can be simplified to 1/x
The 4th expression (x/x^2) can be simplified to 1/x
therefore:
(1/x)-7x+3-(1/x)= -7x+3
b) As for (2x^2)/(7*x^7)
the x^2 cancels out 2 of the 7 in the exponent in the bottom. therefore:
the answer is 2/7x^5
Hope this helps
Sure, okay ooh lets see, oh ok dont worry
So what you need to do is make both of the expressions have the same denominator.
So, what you need to do is multiply 2x by ((x^2)-9) and multiply x by ((2x^2)-7x+3)
Then you'll get
(2x(((x^2)-9))-x(((2x^2)-7x+3)))/((x^2)-7x+3)*((x^2)-9)
There sorry I read it wrong the first time
This should be the right answer