SOLUTION: I've been trying to solve this problem for awhile but I keep messing up because of the fraction in it.
Given the functions f(x)= 4/x^2 and g(x)= 3-2x find
a: the domain of f, g
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-> SOLUTION: I've been trying to solve this problem for awhile but I keep messing up because of the fraction in it.
Given the functions f(x)= 4/x^2 and g(x)= 3-2x find
a: the domain of f, g
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Question 31416: I've been trying to solve this problem for awhile but I keep messing up because of the fraction in it.
Given the functions f(x)= 4/x^2 and g(x)= 3-2x find
a: the domain of f, g, f+g, f-g, fg, and f/g
b: (f+g)(x)
c: (f-g)(x)
d: (fg)(x)
e: (f/g)(x)
f: f(g(x))
g: g(f(x))
I know this seems to be a lot but I really have been stuck and its all part of the same question.
I think I have (fg)(x), I got 4/4x^2-12x+9 ,and I got 4/x^2-2x+3 for (f+g)(x),but I'm not sure if these are correct. Answer by stanbon(75887) (Show Source):
(