SOLUTION: I need help with these problems!!!! PLEASE i have no clue.
1. -x/6 +4 < 1
2. ADD (2b-4) +(8b-6)
3. 6-6(x-2)= 3(3x+1)
4. Subtract (6b+1)-(2b+4)
5. 3y^2(2y^2-1)
6. (-5a^3b)(-ab
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-> SOLUTION: I need help with these problems!!!! PLEASE i have no clue.
1. -x/6 +4 < 1
2. ADD (2b-4) +(8b-6)
3. 6-6(x-2)= 3(3x+1)
4. Subtract (6b+1)-(2b+4)
5. 3y^2(2y^2-1)
6. (-5a^3b)(-ab
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Question 314055: I need help with these problems!!!! PLEASE i have no clue.
1. -x/6 +4 < 1
2. ADD (2b-4) +(8b-6)
3. 6-6(x-2)= 3(3x+1)
4. Subtract (6b+1)-(2b+4)
5. 3y^2(2y^2-1)
6. (-5a^3b)(-ab^2)^3
7. 7x+3x^2-8x = 0
8. (3x^2y^-1)^3/ 18x^3y^2
9. The solution to (x+3)^2 - 25= 0
10. What is the discriminate of 2x^2 - 3x -5 = 0????
Please help me get these answers. Found 2 solutions by Alan3354, unlockmath:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 9. The solution to (x+3)^2 - 25= 0
10. What is the discriminate of 2x^2 - 3x -5 = 0????
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How can you have problems like 9 and 10, when you don't know how to do #2 and #3?
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Getting the answers won't be much help.
9. The solution to (x+3)^2 - 25= 0
(x+3)^2 = 25
Take the square root of both sides
x+3 = ± 5
x = 2
x = -8
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10. What is the discriminate of 2x^2 - 3x -5 = 0????
It's discriminant.
Disc = b^2 - 4ac = 9 - 4*2*(-5) = 9 + 40
Disc = 49
You can put this solution on YOUR website! Hello,
I'll do #3 for you. Let's see if you can do the rest of the problems.
6-6(x-2)= 3(3x+1) This can be rewritten as:
6-6x+12= 9x+3 Combine like terms and add 6x to each side to get:
18=15x+3 Now subtract 3 from both sides to get:
15=15x Divide each side by 15 to get:
x=1
The whole idea is to get x by itself on one side of the equal sign.
To check if it's correct plug the answer into the original problem.
Make sense?
RJ
www.math-unlock.com
