SOLUTION: What is the sine of the inverse sine of square root of 3 divided by 2? In radians and degrees.

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Question 314001: What is the sine of the inverse sine of square root of 3 divided by 2? In radians and degrees.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What is the sine of the inverse sine of square root of 3 divided by 2?
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sin[sin^-1(sqrt(3)/2)]
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= sqrt(3)/2 in radians
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= [sqrt(3)/2][180/pi]
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= 49.62 degrees
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Cheers,
Stan H.






In radians and degrees.