SOLUTION: I need help on finding the least common denominator (LCD) of two rational expressions. How do you find out the LCD for these two? 1/(x^2 - 3x

Click here to see ALL problems on Rational-functions

Question 31400This question is from textbook McDougal Littell Algebra 2
: I need help on finding the least common denominator (LCD) of two rational expressions.
How do you find out the LCD for these two?
1/(x^2 - 3x - 28) , x/ (x^2 +6x + 8) This question is from textbook McDougal Littell Algebra 2

Answer by benni1013(206) (Show Source):
You can put this solution on YOUR website!
First thing to do is factor the bottom for both
1/(x^2-3x-28)==>1/(x+7)(x+4)
x/(x^2+6x+8)==>x/(x+4)(x+2)
To find the common denominator find the things that are similar and disimilar. The things that are disimilar need to be added to the bottom.
(x+4) is in common
(x+7), (x+2) aren't so add them to the denominator
(x+4)(x+7)(x+2) is the lcd.

SOLUTION: I need help on finding the least common denominator (LCD) of two rational expressions. How do you find out the LCD for these two? 1/(x^2 - 3x - 28) , x/ (x^2 +6x + 8)