SOLUTION: Hi again,
I have an equation with a radical inside a radical inside a radical equal to another radical (I'm writing it in exponential form):
(1+(x+(2x+1)^1/2)^1/2)^1/2 = (5+(x)^1
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Rational-functions
-> SOLUTION: Hi again,
I have an equation with a radical inside a radical inside a radical equal to another radical (I'm writing it in exponential form):
(1+(x+(2x+1)^1/2)^1/2)^1/2 = (5+(x)^1
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Question 31390This question is from textbook College Algebra
: Hi again,
I have an equation with a radical inside a radical inside a radical equal to another radical (I'm writing it in exponential form):
(1+(x+(2x+1)^1/2)^1/2)^1/2 = (5+(x)^1/2)^1/2
I tried to square both sides but got lost on the right side after squaring boths sides for the second time coming out with x-3=-x^1/2 after squaring the third time to remove the -x^1/2 remaining on the left side.
Does this equation actually have solutions?
Thank you for all your wonderful help! This question is from textbook College Algebra
You can put this solution on YOUR website! Hi again,
I have an equation with a radical inside a radical inside a radical equal to another radical (I'm writing it in exponential form):
(1+(x+(2x+1)^1/2)^1/2)^1/2 = (5+(x)^1/2)^1/2
IF THIS EQN. MEANS THIS WAY THEN IT HAS A SOLUTION........
(2X+1)^1/2 MEANS ((2X+1)^1)/2=(2X+1)/2...LIKE WISE ALL OTHER TERMS TOO....
THEN THE ANSWER IS X=7.5
IF IT MEANS AS YOU IMPLIED
(2X+1)^0.5...THEN THE ANSWER IS X TENDS TO INFINITY.
I tried to square both sides but got lost on the right side after squaring boths sides for the second time coming out with x-3=-x^1/2 after squaring the third time to remove the -x^1/2 remaining on the left side.
Does this equation actually have solutions?
Thank you for all your wonderful help!
